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Darrell 08-02-2009 10:16 PM

Algebra Help
 
I am taking my math placement for school next Monday and need to freshen up on Algebra. Can anyone recommend a book or website to in a sense "re learn" Algebra?

TIA. :)

markem 08-02-2009 10:22 PM

Re: Algebra Help
 
http://mathworld.wolfram.com/
http://mathforum.org/library/
http://www.mathreference.com/

are all good sites.

ChasDen 08-02-2009 11:03 PM

Re: Algebra Help
 
If
X = the number of cigars you smoke a day and
Y = the number of cigars you have,
Z = The umber of cigars you need to buy this week :D

Help?

Chas

Seriously, good luck, I hate algebra, Loved geometry though.

Starscream 08-03-2009 12:07 AM

Re: Algebra Help
 
Not much of a math person, but if you need any help w/ English Lit. let me know.

The Poet 08-03-2009 01:57 PM

Re: Algebra Help
 
Basic algebra is a breeze - it's once you get into quadratics that the mind goes "WTF?"

TheBeard 08-03-2009 02:30 PM

Re: Algebra Help
 
Quote:

Originally Posted by The Poet (Post 492540)
Basic algebra is a breeze - it's once you get into quadratics that the mind goes "WTF?"

What's so bad about quadratics? What's so bad about polynomials in general?

All of algebra is just knowing how to add, subtract, multiply, divide, and work with equations and inequalities. If you can move symbols around correctly and deal with fractions, then you're set. Sure, there are some nifty facts that "algebra tests" would like you to learn, but that's no more difficult than learning the basic rules to begin with.

TheBeard 08-03-2009 02:34 PM

Re: Algebra Help
 
Quote:

Originally Posted by markem (Post 491824)

I hadn't heard of mathreference.com before now, but I wouldn't point someone to that site (nor to Wolfram's site) for basic algebra help. The mathforum.org site seems to have links to good basic algebra study guides. :)

The Poet 08-03-2009 02:36 PM

Re: Algebra Help
 
Quote:

Originally Posted by TheBeard (Post 492586)
What's so bad about quadratics? What's so bad about polynomials in general?

OK, O Mighty Beard:

2xsuper3 X 4ysuper2 + 6z(a - b over c) over sq.rt d = 7 :fu

TheBeard 08-03-2009 03:09 PM

Re: Algebra Help
 
Quote:

Originally Posted by The Poet (Post 492596)
OK, O Mighty Beard:

2xsuper3 X 4ysuper2 + 6z(a - b over c) over sq.rt d = 7 :fu

Poorly posed question: You've given me one equation with 6 unknowns. What's the question?

The Poet 08-03-2009 03:12 PM

Re: Algebra Help
 
Solve for :fu.

;)

TheBeard 08-03-2009 03:15 PM

Re: Algebra Help
 
Quote:

Originally Posted by The Poet (Post 492654)
Solve for :fu.

;)

:fu = (2x^3 * 4y^22 + 6z(a - b over c))/ (7*sqrt(d))

:pu

The Poet 08-03-2009 03:18 PM

Re: Algebra Help
 
Quote:

Originally Posted by TheBeard (Post 492656)
:fu = (2x^3 * 4y^22 + 6z(a - b over c))/ (7*sqrt(d))

:pu

:r

markem 08-03-2009 07:57 PM

Re: Algebra Help
 
This one looks pretty basic, Darrell. I only scanned a couple of pages, tho.

http://www.intmath.com/Basic-algebra...ebra-intro.php

This one looks okay as well

http://www.mathleague.com/help/algebra/algebra.htm

Darrell 08-04-2009 04:53 PM

Re: Algebra Help
 
Is this Algebra?

2x x 4 = 100

Where the x is 5 making it 25x4=100?

I'm not so good at Math, lol.

markem 08-04-2009 04:57 PM

Re: Algebra Help
 
Quote:

Originally Posted by Darrell (Post 494191)
Is this Algebra?

2x x 4 = 100

Where the x is 5 making it 25x4=100?

I'm not so good at Math, lol.

Yes. It is an equation in a single variable.

However, x is NOT 5. Here's the details

2x X 4 = 100

Divide both sides by 4 and we get

2x = 25

divide both sides by 2 and we get

x = 25/2 = 12.5

Darrell 08-04-2009 05:02 PM

Re: Algebra Help
 
Quote:

Originally Posted by markem (Post 494198)
Yes. It is an equation in a single variable.

However, x is NOT 5. Here's the details

2x X 4 = 100

Divide both sides by 4 and we get

2x = 25

divide both sides by 2 and we get

x = 25/2 = 12.5

So, if the equation is 2x X 4 = 100, will I always take the 100 and divide it by the number that was originally multiplied to get 100? In this case 4.

markem 08-04-2009 05:07 PM

Re: Algebra Help
 
Quote:

Originally Posted by Darrell (Post 494205)
So, if the equation is 2x X 4 = 100, will I always take the 100 and divide it by the number that was originally multiplied to get 100? In this case 4.

Yes, basically. You want to solve for the 'x', so you want to isolate it on one side of the equation and do appropriate add/subtract/multiply/divide until it is my itself.

Here is a slightly more complex example.

2x X 4 + 5 = 85

We want to simplify and getting rid of the "+ 5" on the left means that we subtract 5 from both the right and let sides of the "=" sign.

2x X 4 + 5 - 5 = 85 - 5
2x X 4 = 80

Now, just to simplify more straightforward, note that 2x really means "2 times x" so we can rewrite this as

2 X x X 4 = 80

Let's multiply the 2 and the 4 so we get 8

8 X x = 80

Now divide both sides by 8

x = 10.

Darrell 08-04-2009 05:10 PM

Re: Algebra Help
 
Is simplifying necessary in all equations?

markem 08-04-2009 05:14 PM

Re: Algebra Help
 
Quote:

Originally Posted by Darrell (Post 494218)
Is simplifying necessary in all equations?

At this level of mathematics, it is a good thing to do. Here, we simplified in order to find out what the value of 'x' was, which is what we wanted.

Once you get to more complicated equations, you won't be able to immediately simplify to get an answer. Equations with more than one variable (the famous 'quadratic equations' of high school math are an example), you will put the equations into a certain form and then use a formula to solve the equation (more memorization :mad:). Some times, the equation has more than one (!) answer, even in algebra, but work these things one step at a time.

btw, I didn't mention it before, but if you call your local community college or college/university, they may have someone who can help you plan out what you need to work on. At least up where I'm at, they will do this at no charge (in the hopes that you'll take a class - and pay tuition - from them).


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